3.142 \(\int \frac{(d+e x)^{3/2} (a+b \log (c x^n))}{x^2} \, dx\)

Optimal. Leaf size=259 \[ -3 b \sqrt{d} e n \text{PolyLog}\left (2,1-\frac{2 \sqrt{d}}{\sqrt{d}-\sqrt{d+e x}}\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}+3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )-4 b e n \sqrt{d+e x}-\frac{b d n \sqrt{d+e x}}{x}+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )^2+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )-6 b \sqrt{d} e n \log \left (\frac{2 \sqrt{d}}{\sqrt{d}-\sqrt{d+e x}}\right ) \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \]

[Out]

-4*b*e*n*Sqrt[d + e*x] - (b*d*n*Sqrt[d + e*x])/x + 3*b*Sqrt[d]*e*n*ArcTanh[Sqrt[d + e*x]/Sqrt[d]] + 3*b*Sqrt[d
]*e*n*ArcTanh[Sqrt[d + e*x]/Sqrt[d]]^2 + 3*e*Sqrt[d + e*x]*(a + b*Log[c*x^n]) - ((d + e*x)^(3/2)*(a + b*Log[c*
x^n]))/x - 3*Sqrt[d]*e*ArcTanh[Sqrt[d + e*x]/Sqrt[d]]*(a + b*Log[c*x^n]) - 6*b*Sqrt[d]*e*n*ArcTanh[Sqrt[d + e*
x]/Sqrt[d]]*Log[(2*Sqrt[d])/(Sqrt[d] - Sqrt[d + e*x])] - 3*b*Sqrt[d]*e*n*PolyLog[2, 1 - (2*Sqrt[d])/(Sqrt[d] -
Sqrt[d + e*x])]

________________________________________________________________________________________

Rubi [A]  time = 0.324265, antiderivative size = 259, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 10, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.435, Rules used = {47, 50, 63, 208, 2350, 14, 5984, 5918, 2402, 2315} \[ -3 b \sqrt{d} e n \text{PolyLog}\left (2,1-\frac{2 \sqrt{d}}{\sqrt{d}-\sqrt{d+e x}}\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}+3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )-4 b e n \sqrt{d+e x}-\frac{b d n \sqrt{d+e x}}{x}+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )^2+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )-6 b \sqrt{d} e n \log \left (\frac{2 \sqrt{d}}{\sqrt{d}-\sqrt{d+e x}}\right ) \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \]

Antiderivative was successfully verified.

[In]

Int[((d + e*x)^(3/2)*(a + b*Log[c*x^n]))/x^2,x]

[Out]

-4*b*e*n*Sqrt[d + e*x] - (b*d*n*Sqrt[d + e*x])/x + 3*b*Sqrt[d]*e*n*ArcTanh[Sqrt[d + e*x]/Sqrt[d]] + 3*b*Sqrt[d
]*e*n*ArcTanh[Sqrt[d + e*x]/Sqrt[d]]^2 + 3*e*Sqrt[d + e*x]*(a + b*Log[c*x^n]) - ((d + e*x)^(3/2)*(a + b*Log[c*
x^n]))/x - 3*Sqrt[d]*e*ArcTanh[Sqrt[d + e*x]/Sqrt[d]]*(a + b*Log[c*x^n]) - 6*b*Sqrt[d]*e*n*ArcTanh[Sqrt[d + e*
x]/Sqrt[d]]*Log[(2*Sqrt[d])/(Sqrt[d] - Sqrt[d + e*x])] - 3*b*Sqrt[d]*e*n*PolyLog[2, 1 - (2*Sqrt[d])/(Sqrt[d] -
Sqrt[d + e*x])]

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 2350

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^(r_.))^(q_.), x_Symbol] :> Wit
h[{u = IntHide[(f*x)^m*(d + e*x^r)^q, x]}, Dist[a + b*Log[c*x^n], u, x] - Dist[b*n, Int[SimplifyIntegrand[u/x,
x], x], x] /; ((EqQ[r, 1] || EqQ[r, 2]) && IntegerQ[m] && IntegerQ[q - 1/2]) || InverseFunctionFreeQ[u, x]] /
; FreeQ[{a, b, c, d, e, f, m, n, q, r}, x] && IntegerQ[2*q] && ((IntegerQ[m] && IntegerQ[r]) || IGtQ[q, 0])

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rule 5984

Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*(x_))/((d_) + (e_.)*(x_)^2), x_Symbol] :> Simp[(a + b*ArcTanh[c
*x])^(p + 1)/(b*e*(p + 1)), x] + Dist[1/(c*d), Int[(a + b*ArcTanh[c*x])^p/(1 - c*x), x], x] /; FreeQ[{a, b, c,
d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0]

Rule 5918

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[((a + b*ArcTanh[c*x])^p*
Log[2/(1 + (e*x)/d)])/e, x] + Dist[(b*c*p)/e, Int[((a + b*ArcTanh[c*x])^(p - 1)*Log[2/(1 + (e*x)/d)])/(1 - c^2
*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c^2*d^2 - e^2, 0]

Rule 2402

Int[Log[(c_.)/((d_) + (e_.)*(x_))]/((f_) + (g_.)*(x_)^2), x_Symbol] :> -Dist[e/g, Subst[Int[Log[2*d*x]/(1 - 2*
d*x), x], x, 1/(d + e*x)], x] /; FreeQ[{c, d, e, f, g}, x] && EqQ[c, 2*d] && EqQ[e^2*f + d^2*g, 0]

Rule 2315

Int[Log[(c_.)*(x_)]/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[PolyLog[2, 1 - c*x]/e, x] /; FreeQ[{c, d, e}, x] &
& EqQ[e + c*d, 0]

Rubi steps

\begin{align*} \int \frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x^2} \, dx &=3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )-(b n) \int \frac{-(d-2 e x) \sqrt{d+e x}-3 \sqrt{d} e x \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{x^2} \, dx\\ &=3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )-(b n) \int \left (-\frac{d \sqrt{d+e x}}{x^2}+\frac{2 e \sqrt{d+e x}}{x}-\frac{3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{x}\right ) \, dx\\ &=3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )+(b d n) \int \frac{\sqrt{d+e x}}{x^2} \, dx-(2 b e n) \int \frac{\sqrt{d+e x}}{x} \, dx+\left (3 b \sqrt{d} e n\right ) \int \frac{\tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{x} \, dx\\ &=-4 b e n \sqrt{d+e x}-\frac{b d n \sqrt{d+e x}}{x}+3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )+\left (6 b \sqrt{d} e n\right ) \operatorname{Subst}\left (\int \frac{x \tanh ^{-1}\left (\frac{x}{\sqrt{d}}\right )}{-d+x^2} \, dx,x,\sqrt{d+e x}\right )+\frac{1}{2} (b d e n) \int \frac{1}{x \sqrt{d+e x}} \, dx-(2 b d e n) \int \frac{1}{x \sqrt{d+e x}} \, dx\\ &=-4 b e n \sqrt{d+e x}-\frac{b d n \sqrt{d+e x}}{x}+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )^2+3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )+(b d n) \operatorname{Subst}\left (\int \frac{1}{-\frac{d}{e}+\frac{x^2}{e}} \, dx,x,\sqrt{d+e x}\right )-(4 b d n) \operatorname{Subst}\left (\int \frac{1}{-\frac{d}{e}+\frac{x^2}{e}} \, dx,x,\sqrt{d+e x}\right )-(6 b e n) \operatorname{Subst}\left (\int \frac{\tanh ^{-1}\left (\frac{x}{\sqrt{d}}\right )}{1-\frac{x}{\sqrt{d}}} \, dx,x,\sqrt{d+e x}\right )\\ &=-4 b e n \sqrt{d+e x}-\frac{b d n \sqrt{d+e x}}{x}+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )^2+3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )-6 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \log \left (\frac{2 \sqrt{d}}{\sqrt{d}-\sqrt{d+e x}}\right )+(6 b e n) \operatorname{Subst}\left (\int \frac{\log \left (\frac{2}{1-\frac{x}{\sqrt{d}}}\right )}{1-\frac{x^2}{d}} \, dx,x,\sqrt{d+e x}\right )\\ &=-4 b e n \sqrt{d+e x}-\frac{b d n \sqrt{d+e x}}{x}+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )^2+3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )-6 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \log \left (\frac{2 \sqrt{d}}{\sqrt{d}-\sqrt{d+e x}}\right )-\left (6 b \sqrt{d} e n\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-\frac{\sqrt{d+e x}}{\sqrt{d}}}\right )\\ &=-4 b e n \sqrt{d+e x}-\frac{b d n \sqrt{d+e x}}{x}+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )+3 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )^2+3 e \sqrt{d+e x} \left (a+b \log \left (c x^n\right )\right )-\frac{(d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{x}-3 \sqrt{d} e \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \left (a+b \log \left (c x^n\right )\right )-6 b \sqrt{d} e n \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right ) \log \left (\frac{2 \sqrt{d}}{\sqrt{d}-\sqrt{d+e x}}\right )-3 b \sqrt{d} e n \text{Li}_2\left (1-\frac{2}{1-\frac{\sqrt{d+e x}}{\sqrt{d}}}\right )\\ \end{align*}

Mathematica [A]  time = 0.333317, size = 480, normalized size = 1.85 \[ \frac{-6 b \sqrt{d} e n x \text{PolyLog}\left (2,\frac{1}{2}-\frac{\sqrt{d+e x}}{2 \sqrt{d}}\right )+6 b \sqrt{d} e n x \text{PolyLog}\left (2,\frac{1}{2} \left (\frac{\sqrt{d+e x}}{\sqrt{d}}+1\right )\right )-4 a d \sqrt{d+e x}+8 a e x \sqrt{d+e x}+6 a \sqrt{d} e x \log \left (\sqrt{d}-\sqrt{d+e x}\right )-6 a \sqrt{d} e x \log \left (\sqrt{d+e x}+\sqrt{d}\right )+6 b \sqrt{d} e x \log \left (c x^n\right ) \log \left (\sqrt{d}-\sqrt{d+e x}\right )-4 b d \sqrt{d+e x} \log \left (c x^n\right )+8 b e x \sqrt{d+e x} \log \left (c x^n\right )-6 b \sqrt{d} e x \log \left (c x^n\right ) \log \left (\sqrt{d+e x}+\sqrt{d}\right )-4 b d n \sqrt{d+e x}-16 b e n x \sqrt{d+e x}-3 b \sqrt{d} e n x \log ^2\left (\sqrt{d}-\sqrt{d+e x}\right )+3 b \sqrt{d} e n x \log ^2\left (\sqrt{d+e x}+\sqrt{d}\right )-6 b \sqrt{d} e n x \log \left (\frac{1}{2} \left (\frac{\sqrt{d+e x}}{\sqrt{d}}+1\right )\right ) \log \left (\sqrt{d}-\sqrt{d+e x}\right )+6 b \sqrt{d} e n x \log \left (\sqrt{d+e x}+\sqrt{d}\right ) \log \left (\frac{1}{2}-\frac{\sqrt{d+e x}}{2 \sqrt{d}}\right )+12 b \sqrt{d} e n x \tanh ^{-1}\left (\frac{\sqrt{d+e x}}{\sqrt{d}}\right )}{4 x} \]

Antiderivative was successfully verified.

[In]

Integrate[((d + e*x)^(3/2)*(a + b*Log[c*x^n]))/x^2,x]

[Out]

(-4*a*d*Sqrt[d + e*x] - 4*b*d*n*Sqrt[d + e*x] + 8*a*e*x*Sqrt[d + e*x] - 16*b*e*n*x*Sqrt[d + e*x] + 12*b*Sqrt[d
]*e*n*x*ArcTanh[Sqrt[d + e*x]/Sqrt[d]] - 4*b*d*Sqrt[d + e*x]*Log[c*x^n] + 8*b*e*x*Sqrt[d + e*x]*Log[c*x^n] + 6
*a*Sqrt[d]*e*x*Log[Sqrt[d] - Sqrt[d + e*x]] + 6*b*Sqrt[d]*e*x*Log[c*x^n]*Log[Sqrt[d] - Sqrt[d + e*x]] - 3*b*Sq
rt[d]*e*n*x*Log[Sqrt[d] - Sqrt[d + e*x]]^2 - 6*a*Sqrt[d]*e*x*Log[Sqrt[d] + Sqrt[d + e*x]] - 6*b*Sqrt[d]*e*x*Lo
g[c*x^n]*Log[Sqrt[d] + Sqrt[d + e*x]] + 3*b*Sqrt[d]*e*n*x*Log[Sqrt[d] + Sqrt[d + e*x]]^2 + 6*b*Sqrt[d]*e*n*x*L
og[Sqrt[d] + Sqrt[d + e*x]]*Log[1/2 - Sqrt[d + e*x]/(2*Sqrt[d])] - 6*b*Sqrt[d]*e*n*x*Log[Sqrt[d] - Sqrt[d + e*
x]]*Log[(1 + Sqrt[d + e*x]/Sqrt[d])/2] - 6*b*Sqrt[d]*e*n*x*PolyLog[2, 1/2 - Sqrt[d + e*x]/(2*Sqrt[d])] + 6*b*S
qrt[d]*e*n*x*PolyLog[2, (1 + Sqrt[d + e*x]/Sqrt[d])/2])/(4*x)

________________________________________________________________________________________

Maple [F]  time = 0.504, size = 0, normalized size = 0. \begin{align*} \int{\frac{a+b\ln \left ( c{x}^{n} \right ) }{{x}^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^(3/2)*(a+b*ln(c*x^n))/x^2,x)

[Out]

int((e*x+d)^(3/2)*(a+b*ln(c*x^n))/x^2,x)

________________________________________________________________________________________

Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)*(a+b*log(c*x^n))/x^2,x, algorithm="maxima")

[Out]

Exception raised: ValueError

________________________________________________________________________________________

Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b e x + b d\right )} \sqrt{e x + d} \log \left (c x^{n}\right ) +{\left (a e x + a d\right )} \sqrt{e x + d}}{x^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)*(a+b*log(c*x^n))/x^2,x, algorithm="fricas")

[Out]

integral(((b*e*x + b*d)*sqrt(e*x + d)*log(c*x^n) + (a*e*x + a*d)*sqrt(e*x + d))/x^2, x)

________________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**(3/2)*(a+b*ln(c*x**n))/x**2,x)

[Out]

Timed out

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x + d\right )}^{\frac{3}{2}}{\left (b \log \left (c x^{n}\right ) + a\right )}}{x^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^(3/2)*(a+b*log(c*x^n))/x^2,x, algorithm="giac")

[Out]

integrate((e*x + d)^(3/2)*(b*log(c*x^n) + a)/x^2, x)